Amita has 12 marbles and Reeta has 8 marbles- Reeta says that she has x-y times the marbles that Amita has- where X and y are co-prime numbers- Then x-y-

Since 8 = 2/3 × 12 Reeta has 2/3 times the marbles that Amita has. ∴ x + y = 2 + 3 = 5 ...

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Byju's Answer

Standard VI

Mathematics

Writing a Number as a Product of Its Primes

Amita has 12 ...

Question

Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has $\frac{x}{y}$ times the marbles that Amita has, where $x$ and $y$ are co-prime numbers.

Then $x + y =$ ___

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Solution

Since 8 = $\frac{2}{3}$ × 12

Reeta has $\frac{2}{3}$ times the marbles that Amita has.

$∴ x + y = 2 + 3 = 5$

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Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has xy times the marbles that Amita has, where x and y are co-prime numbers. Then x+y= ___

Since 8 = 23 × 12 Reeta has 23 times the marbles that Amita has. ∴x+y=2+3=5

Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has $\frac{x}{y}$ times the marbles that Amita has, where $x$ and $y$ are co-prime numbers.

Then $x + y =$ ___

Since 8 = $\frac{2}{3}$ × 12

Reeta has $\frac{2}{3}$ times the marbles that Amita has.

$∴ x + y = 2 + 3 = 5$