Amita has $12$ marbles and Reeta has $8$ marbles. Reeta says that she has $x / y$ times the marbles that Amita has, where x and y are co-prime numbers.

Then $x + y =$

___

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Solution

Since $8$ = $\frac{2}{3}$ × $12$

Reeta has $\frac{2}{3}$ times the marbles that Amita has.
$\Rightarrow$ x = $2$ and y = $3$
Therefore, $x + y = 2 + 3 = 5$

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Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has x/y times the marbles that Amita has, where x and y are co-prime numbers. Then x+y= ___

Since 8 = 23 × 12 Reeta has 23 times the marbles that Amita has. ⇒ x = 2 and y = 3 Therefore, x+y=2+3=5

Amita has $12$ marbles and Reeta has $8$ marbles. Reeta says that she has $x / y$ times the marbles that Amita has, where x and y are co-prime numbers.

Then $x + y =$

___

Since $8$ = $\frac{2}{3}$ × $12$

Reeta has $\frac{2}{3}$ times the marbles that Amita has.
$\Rightarrow$ x = $2$ and y = $3$
Therefore, $x + y = 2 + 3 = 5$