Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has x/y times the marbles that Amita has, where x and y are co-prime numbers.

Then x + y =

___

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Solution

Since $8 = \frac{2}{3} \times 12$

Reeta has $\frac{2}{3}$ times the marbles that Amita has.

Therefore, x + y = 2 + 3 = 5

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Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has x/y times the marbles that Amita has, where x and y are co-prime numbers. Then x + y = ___

Since 8=23×12 Reeta has 23 times the marbles that Amita has. Therefore, x + y = 2 + 3 = 5

Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has x/y times the marbles that Amita has, where x and y are co-prime numbers.

Then x + y =

___

Since $8 = \frac{2}{3} \times 12$

Reeta has $\frac{2}{3}$ times the marbles that Amita has.

Therefore, x + y = 2 + 3 = 5