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Ammonia

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Question

Ammonia is used in detection of $C u^{2 +}$ ion because:

aqueous solution of

N H_{3}

reacts with

C u^{2 +}

ion to form deep blue coloured complex

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N H_{3}

reacts with

C u^{2 +}

ion to give blue precipitate of

C u O

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aqueous solution of

N H_{3}

reacts with

C u^{2 +}

ion to form white coloured complex.

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N H_{3}

reacts with

C u^{2 +}

ion to give green precipitate.

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Solution

The correct option is A aqueous solution of $N H_{3}$ reacts with $C u^{2 +}$ ion to form deep blue coloured complex

Ammonia acts as a Lewis base due to the presence of lone pair of on the nitrogen atom.so,it can form coordinate bond transition metal cations to from complex compounds.Ammonia reacts with a solution of $C u^{2 +}$ to from a deep blue coloured complex.The reaction for the above complex compound can be written as follows:

$C u^{2 +} (a q) + 4 N H_{3} (a q) \to [C u (N H_{3})_{4}]^{2 +} (a q)$

Deep Blue
Hence option A is correct.

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Similar questions

Q. In the excess of

N H_{3} (a q .), C u^{2 +}

ions forms a deep blue complex ion

{[C u {(N H_{3})}_{4}]}^{+ 2}

which has

K_{f} = 10^{11}

the concentration of

C u^{2 +}

ion in solution prepared by adding

5 \times 10^{- 3}

moles of

C u S O_{4}

0.5 L

0.4 M N H_{3} (a q)

State True or False.

Both

C u^{2 +}

and

C d^{2 +}

ions react with KCN to form complex.

{C u}^{2 +}

gives white ppt of

{C u}_{2} I_{2}

with

K I

and deep blue colour of

[{C u ({N H}_{3})}_{4}]^{2 +}

with aq.

{N H}_{3}

(excess).

If the given statement is true enter 1 else enter 0.

{C u}^{2 +}

ions react with

{F e}^{2 +}

ions according to the following reaction:

{C u}^{2 +} + 2 {F e}^{2 +} ⇌ C u + 2 {F e}^{3 +}

At equilibrium, the concentration of

{C u}^{2 +}

ions is not changed by the addition of:

Q. On adding

N a O H

to ammonium sulphate, a colourless gas with pungent odour is evolved which forms a blue coloured complex with

C u^{2 +}

ion. Identify the gas.

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Ammonia is used in detection of Cu2+ ion because:

Ammonia is used in detection of $C u^{2 +}$ ion because: