Question

Ammonia, $N{H}_3$ and hydrazine $N_2{H}_4$, are both binary compounds of nitrogen and hydrogen. Based on the law of multiple proportions, how many milligrams of hydrogen would you expect $2.34g$ of nitrogen to combine with to yield ammonia?

Write your answer in integer.

Answer 1

According to the law of multiple proportions, $28$ g of N combine with $6$ g and $4$ g of H to form $N{H}_3$ and $N_2{H}_4$.

Hence, $2.34$ g of N will combine with $\frac{6}{28}\times 2.34=0.501g$ of H to form $N{H}_3$. This corresponds to $501$ mg.