Ammonia reacts with excess of chlorine to form:

N_{2}

and

N H_{4} C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N C l_{3}

and

H C l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N H_{4} C l

and

N C l_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2}

and

H C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $N C l_{3}$ and $H C l$
With excess of chlorine:
$N H_{3} + 3 C l_{2} \to N C l_{3} + 3 H C l$

Suggest Corrections

Similar questions

Q. An excess of

C l_{2}

reacts with ammonia, the products formed are:

$N H_{4} C l$ + $N a N O_{2} \to$ ____ + ____

Q. Which of the following reactions is/are correct when

C l_{2}

reacts with

N H_{3}

(a) What type of bond is formed between two atoms, when the difference in electronegativity between them is
(i) high, (ii) low, (iii) zero?
(b) Separate the following compounds into three categories- ionic, polar and covalent compounds; N₂, NH₄Cl, NH₃, NO, NH₄NO₃, NCl₃.

Q. Balance the chemical equation given below and calculate the number of moles of

N H_{4} C l

formed when 16 moles of

N H_{3}

react with 6 moles of

C l_{2}

gas.

N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

Join BYJU'S Learning Program

Ammonia reacts with excess of chlorine to form:

The correct option is B NCl3 and HClWith excess of chlorine:NH3+3Cl2→NCl3+3HCl

The correct option is B $N C l_{3}$ and $H C l$
With excess of chlorine:
$N H_{3} + 3 C l_{2} \to N C l_{3} + 3 H C l$