Ammonia reacts with excess of chlorine to form :

N_{2} + N H_{4} C l

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N {C l}_{3}

and

H C l

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N H_{4} C l

and

N {C l}_{3}

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N_{2}

and

H C l

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Solution

The correct option is B $N {C l}_{3}$ and $H C l$
Pure chlorine gas may react vigorously with ammonia gas. An excessive mix of the two gases in air can produce hazardous compounds such as nitrogen trichloride.
The following reaction takes place:
$N H_{3} + 3 {C l}_{2} ⟶ N {C l}_{3} + 3 H C l$
Ammonia reacts with excess of chlorine to form $N {C l}_{3}$ and $H C l$ .

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Similar questions

Q. An excess of

C l_{2}

reacts with ammonia, the products formed are:

$N H_{4} C l$ + $N a N O_{2} \to$ ____ + ____

Q. Which of the following reactions is/are correct when

C l_{2}

reacts with

N H_{3}

(a) What type of bond is formed between two atoms, when the difference in electronegativity between them is
(i) high, (ii) low, (iii) zero?
(b) Separate the following compounds into three categories- ionic, polar and covalent compounds; N₂, NH₄Cl, NH₃, NO, NH₄NO₃, NCl₃.

Q. Balance the chemical equation given below and calculate the number of moles of

N H_{4} C l

formed when 16 moles of

N H_{3}

react with 6 moles of

C l_{2}

gas.

N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

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