MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Types of Crystalline Solids

Ammonium chlo...

Question

Ammonium chloride crystallises in a body centered cubic lattice with a unit distance of $386 p m$ . Calculate the radius (in pm) of $N H_{4}^{+}$ ion. If the radius of $C l^{-}$ ion is $181 p m$
$(T a k e \sqrt{3} = 1.73)$

Open in App

Solution

In a body- centered cubic lattice, oppositely charged ions touch each other along the cross- diagonal of the cube.
So,
$2 r_{c} + 2 r_{a} = \sqrt{3} a$
$\Rightarrow r_{c} + r_{a} = \frac{\sqrt{3}}{2} a$
$= \frac{\sqrt{3}}{2} \times 386 = 333.89 p m$
Given that,
$r_{a} = 181 p m$
$∴ r_{c} = (333.89 - 181.0) p m = 152.89 p m$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Ammonium chloride crystallises in a body centered cubic lattice with a unit distance of

386 p m

. Calculate the radius (in pm) of

N H_{4}^{+}

ion. If the radius of

C l^{-}

181 p m

(T a k e \sqrt{3} = 1.73)

Q. Ammonium chloride crystallises in a body-centred cubic lattice with a unit distance of 387 pm. Calculate (a) the distance between oppositely charged ions in the lattice and (b) the radius of the

N H_{4}^{+}

ion if the radius of

C l^{-}

ions is 181 pm.

N H_{4} C l

crystallizes in a body centred cubic lattice , with a unit cell distance of

387 p m

. Calculate the radius of the

N H_{4}^{+}

ion if the radius of the

C l^{-}

181 p m

.

Q. Ammonium chloride cystallise in a body-centred cubic lattice with a unit distance of

387 p m

. Calculate
(a) the distance between oppositely charged ion in the lattice and
(b) the radius of the

{N H}_{4}^{+}

ion if the radius of

{C l}^{-}

181 p m

Q. Ammonium chloride crystallizes in a body-centered cubic lattice with a unit distance of

387

pm. If the size of

C l^{-}

181

pm, the size of

N H_{4}^{+}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Types of Crystalline Solids

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Types of Crystalline Solids

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon