Ammonium dichromate on heating decompose to form nitrogen and chromium ( lll) oxide and water what will be the loss in mass if 31.5 gram of Ammonium dichromate is heated at 100°C
(chromium=52,nitrogen=14,hydrogen=1,oxygen =16)
(NH4 )²Cr2O7 gives N2+Cr2O3+4H2O

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Solution

(i) (NH₄)₂Cr₂O₇ -> N₂+Cr₂O₃+4H₂O
252gm = 22.4 litres of N₂
31.5gm = ( 22.4/252)* 31.5
= 2.8 litres

(ii) If 252gm of (NH₄)₂Cr₂O₇ is heated then
loss of wt. is =28gms due to N₂
31.5gm.--------- =(28/252)*31.5
=3.5gm

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(NH₄)₂Cr₂O₇ $\overset{}{\to}$ N₂ + Cr₂O₃ + 4H₂O. What volume of nitrogen at STP, will be evolved when 63 g of ammonium dichromate is decomposed? (H = 1, N = 14, O = 16, Cr = 52)

Solid ammonium dichromate decomposes as the equationr:

$(N H_{4} 4)_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O$
If 63 g of sammonium dichromate decomposes, calculate:
(a) the quantity in moles of $(N H_{4})_{2} C r_{2} O_{7}$
(b) the qunatity in moles of nitrogen formed
(c) the volume of $N_{2}$ evolved at STP

(d) the loss of mass
(e) the mass of chromium (iii) oxide formed at the same time.

Q. Give chemical reaction for:-

A m m o n i u m d i c h r o m a t e \to C h r o m i u m o x i d e + W a t e r + N i t r o g e n

(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}

Calculate the volume of nitrogen at STP, evolved when 63 g of ammonium dichromate is heated.

(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}

The mass of

C r_{2} O_{3}

formed by the decomposition of 63 gm of ammonium dichromate :

[N = 14, H = 1, O = 16, C r = 52]

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Ammonium dichromate on heating decompose to form nitrogen and chromium ( lll) oxide and water what will be the loss in mass if 31.5 gram of Ammonium dichromate is heated at 100°C (chromium=52,nitrogen=14,hydrogen=1,oxygen =16) (NH4 )²Cr2O7 gives N2+Cr2O3+4H2O

(i) (NH4)2Cr2O7 -> N2+Cr2O3+4H2O 252gm = 22.4 litres of N2 31.5gm = ( 22.4/252)* 31.5 = 2.8 litres (ii) If 252gm of (NH4)2Cr2O7 is heated then loss of wt. is =28gms due to N2 31.5gm.--------- =(28/252)*31.5 =3.5gm

Ammonium dichromate on heating decompose to form nitrogen and chromium ( lll) oxide and water what will be the loss in mass if 31.5 gram of Ammonium dichromate is heated at 100°C
(chromium=52,nitrogen=14,hydrogen=1,oxygen =16)
(NH4 )²Cr2O7 gives N2+Cr2O3+4H2O

(i) (NH₄)₂Cr₂O₇ -> N₂+Cr₂O₃+4H₂O
252gm = 22.4 litres of N₂
31.5gm = ( 22.4/252)* 31.5
= 2.8 litres

(ii) If 252gm of (NH₄)₂Cr₂O₇ is heated then
loss of wt. is =28gms due to N₂
31.5gm.--------- =(28/252)*31.5
=3.5gm