CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

(NH4)2Cr2O7 N2 + Cr2O3 + 4H2O. What volume of nitrogen at STP, will be evolved when 63 g of ammonium dichromate is decomposed? (H = 1, N = 14, O = 16, Cr = 52)

Open in App
Solution

Let V be the volume of nitrogen evolved in litres.
Molecular mass of ammonium dichromate = [4(14) + 8(1) + 2(52) + 7(16)] g = 252 g
Number of moles in 63 g of ammonium dichromate = 63252 = 0.25

According to the balanced chemical equation, one mole of dichromate decomposes to give one mole of nitrogen.
Thus, 0.25 mole of dichromate will decompose to give 0.25 mole of nitrogen.

Number of moles of nitrogen at STP = Volume of nitrogenMolar volume= V22.4
V22.4=63252

V = 5.6 L


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Covalent Bonds
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon