$(N H_{4})_{2} C r_{2} O_{7} h e a t \to N_{2} (g) + 4 H_{2} O (g) + C r_{2} O_{3}$

The volume in litres of dm $^{3}$ of $N_{2}$ evolved when 63 gm of ammonium dichromate is heated at STP is____________. (Please give your answer in the form of nearest integer)

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Solution

Gram molecular mass of $(N H_{4})_{2} C r_{2} O_{7}$ = $252$ g.

Gram molecular mass of $N_{2}$ = $28$ g.

Gram molecular mass of $C r_{2} O_{3}$ = $152$ g.

If $252$ g of $(N H_{4})_{2} C r_{2} O_{7}$ release $22.4$ litres of $N_{2}$ at STP.

then, $63$ g of $(N H_{4})_{2} C r_{2} O_{7}$ will release $\frac{22.4 \times 63}{252} = 5.59 l i t r e s$ $\approx 6 L$

Hence, the correct answer is $6$ .

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(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}

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(NH4)2Cr2O7heat→N2(g)+4H2O(g)+Cr2O3The volume in litres of dm3 of N2 evolved when 63 gm of ammonium dichromate is heated at STP is____________. (Please give your answer in the form of nearest integer)

Gram molecular mass of (NH4)2Cr2O7 =252 g.Gram molecular mass of N2 = 28g.Gram molecular mass of Cr2O3 = 152 g.If 252g of (NH4)2Cr2O7 release 22.4 litres of N2 at STP.then, 63g of (NH4)2Cr2O7 will release 22.4×63252=5.59 litres ≈6LHence, the correct answer is 6.

$(N H_{4})_{2} C r_{2} O_{7} h e a t \to N_{2} (g) + 4 H_{2} O (g) + C r_{2} O_{3}$

The volume in litres of dm $^{3}$ of $N_{2}$ evolved when 63 gm of ammonium dichromate is heated at STP is____________. (Please give your answer in the form of nearest integer)