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Question

Among LiCl, BeCl2, BCl3 and CCl4, the covalent bond character varies as :

A

LiCl < BeCl2> BCl3> CCl4

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B

LiCl > BeCl2< BCl3< CCl4

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C

LiCl < BeCl2< BCl3< CCl4

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D

LiCl > BeCl2> BCl3> CCl4

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Solution

The correct option is C

LiCl < BeCl2< BCl3< CCl4


Covalent character increases up to middle of the period

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