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Question

Among LiCl, BeCl2, BCl3 and CCl4 the covalent charecter varies as:

A
LiCl<BeCl2>BCl3>CCl4
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B
LiCl>BeCl2<BCl3<CCl4
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C
LiCl<BeCl2<BCl3<CCl4
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D
LiCl>BeCl2>BCl3>CCl4
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Solution

The correct option is C LiCl<BeCl2<BCl3<CCl4
According to fajan's rule,more the charge on cation,more would be polarizing power and more would be the covalent character.
Li+,Be2+,B3+,C4+
LiCl<BeCl2<BCl3<CCl4
Hence, option C is the correct answer.

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