Among ${N H}_{3}, H_{2} O$ and $H F$ , which would you expect to have highest magnitude of hydrogen bonding and why?

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Solution

$H_{2} O$ has the highest magnitude of $H -$ bonding.
The extent of $H -$ bonding depends upon electronegativity and the number of $H -$ atoms available for bonding. Although $F$ is more electronegative than oxygen, the extent of $H -$ bonding is higher in water. There is a shortage of $H$ in $H F$ , whereas there are exactly the right numbers of $H$ in $H_{2} O$ . Hence oxygen forms a huge ring like structure. In case of $N H_{3}$ , the $H -$ bonding is limited because $N$ has only one lone pair.

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Question 04

Hydrogen bonds are formed in many compounds e.g., $H_{2} O, H F, N H_{3}$ . The boiling point of such compounds depends to a extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points above compounds is

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(d) $N H_{3} > H_{2} O > H F$

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Among NH3,H2O and HF, which would you expect to have highest magnitude of hydrogen bonding and why?

Among ${N H}_{3}, H_{2} O$ and $H F$ , which would you expect to have highest magnitude of hydrogen bonding and why?