Among $N H_{3}, H_{2} O, H F$ and $H_{2} S$ which have the highest magnitude of hydrogen bonding?

H F

due to maximum polarity

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} O

due to lone pairs of electrons

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N H_{3}

due to small size of bitrogen

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S

due to higher electron affinity of sulphur

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $H F$ due to maximum polarity
Fluorine is the most electronegative element. $H - F$ bond has maximum bond polarity. Hence, hydrogen bonding is maximum in $H F$ molecules.

Suggest Corrections

Similar questions

Q. Among

{N H}_{3}, H_{2} O

and

H F

, which would you expect to have highest magnitude of hydrogen bonding and why?

Q. Represent with the help of neat diagrams hydrogen bonding if present in the molecules of

H F

- H_{2} O

H F

- {N H}_{3}

, aniline

-

aniline,

H_{2} O

- C_{2} H_{5} O H

H_{2} O

- {C H}_{3} {O C H}_{3}

H_{2} O

- H_{2} {S O}_{4}

H_{2} O

- N a C l

Question 04

Hydrogen bonds are formed in many compounds e.g., $H_{2} O, H F, N H_{3}$ . The boiling point of such compounds depends to a extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points above compounds is