Among the complex ions, ${[C o (N H_{2} - C H_{2} - C H_{2} - N H_{2})_{2} C l_{2}]}_{2}^{+}, {[C r C l_{2} (C_{2} O_{4})_{2}]}_{2}^{3 -}, {[F e (H_{2} O)_{4} (O H)_{2}]}_{2}^{+}, {[F e (N H_{3})_{2} (C N)_{4}]}_{3}^{-}, {[C o (N H_{2} - C H_{2} - C H_{2} - N H_{2})_{2} (N H_{3}) C l]}_{2}^{2 +} a n d {[C o (N H_{3})_{4} (H_{2} O) C l]}_{3}^{2 +}$ , the number of complex ions that show cis - trans isomeroism is:

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Solution

Here, we know that $N H_{2} - C H_{2} - C H_{2} - N H_{2}$ is nothing but en. $C_{2} O_{4}^{2 -}$ is ox.
So now our complexes look like ${[C o (e n)_{2} C l_{2}]}_{2}^{+}, {[C r C l_{2} (o x)_{2}]}_{2}^{3 -}, {[F e (H_{2} O)_{4} (O H)_{2}]}_{2}^{+}, {[F e (N H_{3})_{2} (C N)_{4}]}_{3}^{-}, {[C o (e n)_{2} (N H_{3}) C l]}_{2}^{2 +} a n d {[C o (N H_{3})_{4} (H_{2} O) C l]}_{3}^{2 +}$
All of the above complexes will show geometrical isomerism. Hence, the total number is 6.

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Similar questions

[C o (N H_{2} - C H_{2} - C H_{2} - N H_{2})_{2} C l_{2}]^{+}, [C r C l_{2} (C_{2} O_{4})_{2}]^{3 -}, [F e (H_{2} O)_{4} (O H)_{2}]^{+}, [F e (N H_{3})_{2} (C N)_{4}]^{-}, [C o (N H_{2} - C H_{2} - C H_{2} - N H_{2})_{2} (N H_{3}) C l]^{2 +}

[C o (N H_{3})_{4} (H_{2} O) C l]^{2 +}

{[C o (N H_{2} - C H_{2} - C H_{2} - N H_{2})_{2} C l_{2}]}_{2}^{+}, {[C r C l_{2} (C_{2} O_{4})_{2}]}_{2}^{3 -}, {[F e (H_{2} O)_{4} (O H)_{2}]}_{2}^{+}, {[F e (N H_{3})_{2} (C N)_{4}]}_{3}^{-}, {[C o (N H_{2} - C H_{2} - C H_{2} - N H_{2})_{2} (N H_{3}) C l]}_{2}^{2 +} a n d {[C o (N H_{3})_{4} (H_{2} O) C l]}_{3}^{2 +}

(i) [C o (N H_{3})_{4} (H_{2} O) C l]^{2 +} (i i) [P t (N H_{3})_{2} C l_{2}] (i i i) [C o C l_{2} (e n)_{2}]^{+} (i v) [C r (H_{2} O)_{5} C l] C l_{2} (v) [F e (N H_{3})_{2} (C N)_{4}]^{-} (v i) [C r C l_{2} (o x)_{2}]^{3 -} (v i i) K [C o (H_{2} O)_{2} (o x)_{2}] (v i i i) [C o (N H_{3})_{2} C l_{2} (e n)]^{+} (i x) [C o (e n)_{3}] C l_{3}

cis-trans

C_{6} H_{5} + C H_{2}, p - (C H_{3} O) C_{6} H_{4} + C H_{2}, p - (N O_{2}) C_{6} H_{4} + C H_{2}

p - (C H_{3}) C_{6} H_{4} + C H_{2}

C H_{3} C H = C H_{2}

C H_{3} C H = C H C H_{2} C H_{3}

C H_{3} C H = C H C H_{3}

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