Among the following compounds, which has the maximum number of sp-hybridized atoms?

(C H)_{2}

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C H_{2} = C = C H - C N

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H C \equiv C - C H_{2} - C H_{3}

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H C \equiv C - C N

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Solution

The correct option is A $H C \equiv C - C N$
sp hybridization is seen in triple bond
formation carbon
$\Rightarrow H C \equiv C - C \equiv N$ has the maximum numbers
of sp-hybridized atoms i.e., 3
$⋆ H C \equiv C -$ have triple bond b/w two C-atoms
$⋆ - C \equiv N$ has triple bond with a nitrogen

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s p - s p^{3}

\begin{matrix} C H_{2} = C = C H & - & C H & - & C & \equiv & C H | C N \end{matrix}

C H_{3} - C H_{3}, C H_{2} = C H - C H_{3}, H C \equiv C - C H_{3}

C - C

H C \equiv C - C H = C H_{2}

H C \equiv C - C H_{2} - C H_{2} = C H C H_{2} - | C = C H - H | C = O

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