Among the following, find the one which is not an oxidation-reduction reaction?

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l)

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N a O H (a q) + H C l (a q) \to N a C l (a q) + H_{2} O (l)

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H_{2} O_{2} (l) \to H_{2} O (l) + O_{2} (g)

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{C H}_{4} (g) + O_{2} (g) \to H_{2} O (g) + {C O}_{2} (g)

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M g (s) + 2 H C l (a q) \to M g {C l}_{2} (a q) + H_{2} (g)

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Solution

The correct option is B $N a O H (a q) + H C l (a q) \to N a C l (a q) + H_{2} O (l)$
The reaction which is not an oxidation-reduction reaction is
$N a O H (a q) + H C l (a q) \to N a C l (a q) + H_{2} O (l)$
This is an acid base neutralisation reaction. Acid reacts with base to form salt and water.

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Similar questions

Complete and balance the following reaction:

${CH}_{4} (g) + O_{2} (g) \to$

C (s) + O_{2} (g) \to C O_{2} (g) + 94.2 K c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) + 68.3 K c a l

C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l) + 210.8 K c a l

C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) ⟶ 2 {C O}_{2} (g) + H_{2} O (l); △ G^{0} = 1234 k J

C (s) + O_{2} (g) ⟶ {C O}_{2} (g); △ G^{0} = - 394 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); △ G^{0} = - 237 k J

H_{2} (g) + 2 C (s) \to C_{2} H_{2} (g)

C (s) + O_{2} (g) \to C O_{2} (g) Δ H = + 94.2 k c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) + 68.3 Δ H = k c a l

C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l) Δ H = + 210.8 k c a l

k c a l

Δ H \neq Δ U

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