Among the following, the correct order of acidity is

H C l O_{3} < H C l O_{4} < H C l O_{2} < H C l O

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H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

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H C l O_{2} < H C l O < H C l O_{3} < H C l O_{4}

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H C l O_{4} < H C l O_{2} < H C l O < H C l O_{3}

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Solution

The correct option is B $H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}$
The increasing order of acidity is $H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}$
+1 +3 +5 +7

The acidic character of the oxyacids of halogens increases with an increase in the oxidation number of halogens.

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Similar questions

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O_{4} < H C l O_{3} < H C l O_{2} < H C l O

H C l O, H C l O_{2}, H C l O_{3}, H C l O_{4}

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