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Oxides of Nitrogen

Among the oxi...

Question

Among the oxides of nitrogen: $N_{2} O_{3}, N_{2} O_{4}$ and $N_{2} O_{5}$ ; the molecule(s) having nitrogen-nitrogen bond is/are:

Only

N_{2} O_{5}

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N_{2} O_{3}

and

N_{2} O_{4}

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N_{2} O_{3}

and

N_{2} O_{5}

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N_{2} O_{4}

and

N_{2} O_{5}

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Solution

The correct option is A $N_{2} O_{3}$ and $N_{2} O_{4}$
Among the oxides of nitrogen: $N_{2} O_{3}, N_{2} O_{4}$ and $N_{2} O_{5}$ ; the molecule(s) having nitrogen-nitrogen bond are
$N_{2} O_{3}$ and $N_{2} O_{4}$ . Whereas, $N_{2} O_{5}$ has nitrogen-oxygen bonds only.

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Similar questions

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2},

\frac{- d}{d t} [N_{2} O_{5}] = k_{1} [N_{2} O_{5}], \frac{d}{d t} [N O_{2}] = k_{2} [N_{2} O_{5}] a n d

\frac{d}{d t} [O_{2}] = k_{3} [N_{2} O_{3}],

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2} .

G i v e n : - \frac{d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = K_{2} [N_{2} O_{5}]

A n d \frac{d [O_{2}]}{d t} = K_{3} [N_{2} O_{5}]

The relation between $K_{1}, K_{2}$ and $K_{3}$ is

N_{2} O_{5} ⟶ 2 N O_{2} + 1 / 2 O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

k_{1}, k_{2}

k_{3}

N_{2} O_{5}

N_{2} O_{5} (g) ⇌ N_{2} O_{3} (g) + O_{2} (g); K_{c} = 2.5

N_{2} O_{3}

N_{2} O_{3} (g) ⇌ N_{2} O + O_{2} (g)

4.0

N_{2} O_{5}

1.0

O_{2}

2.5 M

N_{2} O_{5}

N_{2} O_{5}

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