Among the oxyacids of chlorine, the strongest oxidising agent is:

H C l O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H C l O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H C l O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H C l O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $H C l O_{4}$
$H + 7 C l O_{4}$ is strongest oxidising agent.
as Cl is in its highest oxidation state, i.e., +7.
Oxidation state $α$ Oxdising nature

Suggest Corrections

Similar questions

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

Of the four oxyacids of chlorine the strongest oxidising agent in dilute aqueous solution is

{H C l O}_{4}

{H C l O}_{3}

{H C l O}_{2}

H O C l

H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O

Join BYJU'S Learning Program