wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A
motor car is going due north at a speed of 50 km/h. It makes a 90 left turn
without changing the speed. The change in the velocity of the car is about:

A
50 km/h towards west
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
70 km/h towards south- west
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
70 km/h towards north-west
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 70 km/h towards south- west
Initial velocity = vi=50j
FInal velocity =vf=50i
Change in velocity = Δv=vfvi=50i50j
Negative x- means west direction and negative y-component means south direction. Hence resultant velocity is in south-west direction.
Magnitude of change in velocity = (502)+(502)) = 70. 71 km/h


945013_1803_ans_28b06c3448ed4d2095a349f367cc8538.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Operations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon