Ample 1-11 The electric field components in Fig- 1-27 areEr - ax1-2- Ey - Ez - 0- in which - - 800 N-C m1-2- Calculate -a- theflux through the cube- and -b- the charge within the cube- Assumethat a- 0-1 m-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Electric Field Due to Disk and Infinitely Large Sheet

ample 1.11 Th...

Question

ample 1.11 The electric field components in Fig. 1.27 areEr = ax1/2, Ey = Ez = 0, in which α = 800 N/C m1/2. Calculate (a) theflux through the cube, and (b) the charge within the cube. Assumethat a= 0.1 m.

Open in App

Solution

Suggest Corrections

Similar questions

The electric field components in the figure are $E_{x} = α x^{1 / 2}, E_{y} = 0, E_{z} = 0$ where $α = 800 N / m^{2}$ . If a = 0.1 m is the side of cube then the charge within the cube is:

Q. The electric field components due to a charge inside the cube of side 0.1 m are shown in figure.
where,

E_{x} = α

, where

α

= 500 N/C-m,

E_{y}

= 0,

E_{z} = 0

Calculate

(a) the flux through the cube and
(b) the charge inside the cube.

Q. The electric field components in figure are

E_{x} = b \sqrt{x}, E_{y} = E_{z} = 0,

Calculate the net flux through the cube.

Q. The electric field components in the given figure are

E_{x} = α x^{1 / 2}, E_{y} = E_{z} = 0

in which

α = 800 N C^{- 1} m^{- 1 / 2}

. The charge within the cube is, if net flux through the cube is

1.05 N m^{2} C^{- 1}

(assume

a = 0.1 m

)

The electric field components in the given figure are $E_{x} = α x^{\frac{1}{2}}, E_{y} = E_{z} = 0$ in which $α = 800 N C^{- 1} m^{\frac{- 1}{2}}$ . The charge within the cube is if net flux through the cube is $1.05 N m^{2} C^{- 1}$ (assume a = 0.1 m)

Join BYJU'S Learning Program