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Amplitude of ...

Question

Amplitude of a sinusoidally oscillating electric field of a plane electromagnetic wave is 60v/m. Then the magnitude of magnetic field will be?

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Solution

dear student

electric field= magnetic field $\times$ speed of em wave
so
B=E/c= $60 / (3 \times 10^{8}) = 20 \times 10^{- 8} = 2 \times 10^{- 7} T$

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