Question

$△AMT\sim △AHE.$ In $△AMT,AM=6.3cm,\angle TAM={50}^{\circ }$, $AT=5.6cm.\frac{AM}{AH}=\frac{7}{5}.$ Construct $△AHE.$

Answer 1

Steps of Construction:

Step 1: Draw ∆AMT such that AM = 6.3 cm, ∠TAM = 50°, AT = 5.6 cm.

Step 2: Divide segment AM into 7 equal parts.

Step 3: Name the end point of the 5th part of segment AM as H.

Step 4: Draw a line parallel to side TM, through H. Name the point where the parallel line intersects AT as E.


Here, ∆AMT ~ ∆AHE.