An $80 kg$ person is parachuting and is experiencing a downward acceleration of $2.8 {m/s}^{2}$ . The mass of the parachute is $5 kg$ . The net force on the system (parachute+man) is (Take ${g=9.8 m/s}^{2}$ ):

238 N

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675 N

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456 N

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925 N

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Solution

The correct option is A $238 N$

The net downward acceleration is $2.8 m / s^{2}$
According to Newton second law
$F = m a$
$m$ = $80 + 5 = 85$ $k g$
Hence $F = 85 \times 2.8$ N = $238 N$

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An 80kg person is parachuting and is experiencing a downward acceleration of 2.8m/s2. The mass of the parachute is 5kg. The net force on the system (parachute+man) is (Take g=9.8 m/s2):

The correct option is A 238N The net downward acceleration is 2.8m/s2According to Newton second law F=mam=80+5=85 kgHence F=85×2.8N = 238N

An $80 kg$ person is parachuting and is experiencing a downward acceleration of $2.8 {m/s}^{2}$ . The mass of the parachute is $5 kg$ . The net force on the system (parachute+man) is (Take ${g=9.8 m/s}^{2}$ ):

The correct option is A $238 N$

The net downward acceleration is $2.8 m / s^{2}$
According to Newton second law
$F = m a$
$m$ = $80 + 5 = 85$ $k g$
Hence $F = 85 \times 2.8$ N = $238 N$