Question

An 800 W, 220 V kettle and three 100 W, 220 V bulbs are connected in parallel across. The current drawn from the source is

• A. 6.9 A
• B. 5.5 A
• C. 5.0 A
• D. 0.15 A

Answer 1

The correct option is C 5.0 A

Current through the kettle is
$I_1=\frac{P}{V}$
$I_1=\frac{800}{220}$
Current through the bulb
$I_2=\frac{100}{220}$
Total current is
$I=I_1+3I_2=\frac{800}{220}+3\frac{100}{220}$

$HenceI=\frac{1100}{220}=5A$