Question

An AC source of voltage $E=20\sin 100t$ is connected across a resistance $20\Omega$. The rms value of current in the circuit is

• A. $1A$
• B. $\frac{1}{2}A$
• C. $\sqrt{2}A$
• D. $2\sqrt{2}A$
• E. $\frac{1}{\sqrt{2}}A$

Answer 1

The correct option is E $\frac{1}{\sqrt{2}}A$

Since, $I_o=\frac{E_o}{R}$

$I_o=\frac{20}{20}=1A$

$I_{rms}=\frac{I_o}{\sqrt{2}}$

$I_o=\frac{1}{\sqrt{2}}A$