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Question

An AC voltage source has an output of ΔV=(200V)sin2πft. This source is connected to a 100Ω resistor. RMS current in the resistance is

A
1.41A
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B
2.41A
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C
3.41A
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D
0.71A
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Solution

The correct option is C 1.41A
On comparing the given source voltage with V=Vosinwt
We get, Vo=200 volts
Rms voltage of source Vrms=Vo2=2002=1002 volts
Thus rms current Irms=VrmsR where R=100Ω
Irms=1002100=2=1.41A

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