An acid solution st pH $= 6$ is diluted hundred times. The approximate pH of the solution becomes

6.96

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Solution

The correct option is B 6.96
$p H = 6 \Rightarrow [H^{+}] = 10^{- 6} M = M_{1}$
When diluted 100 times $\Rightarrow \frac{V_{2}}{V_{1}}$ $= 100$
$M_{1} V_{1} = M_{2} V_{2}$
$M_{2} = M_{1} \frac{V_{1}}{V_{2}} = \frac{10^{- 6}}{100} = 10^{- 8} M$
$p H = - l o g (10^{- 8} + 10^{- 7}) = 6.96$

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