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Question

An adult weighing 600 N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs for 6 km, calculate the energy utilised by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting 10% of energy intake in the form of food, calculate the energy equivalents of food that would be required to compensate energy utilised for jogging.


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Solution

Step:1 Calculate the energy utilised by the adult.

Formula Used: E=mgh

In 6 km there are 6000 steps.

In one step energy utilised is E=mgh

In 6000 steps E=6000(mg)h

=6000×600×0.25

=9×105J.

Step:2 Calculate the energy equivalents of food that would be required to compensate energy utilised for jogging.

As the above is 10% of energy intake.

Therefore, the intake energy = 10 E=9×106J.

Final Answer: 9×106J.

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