Question

An adult weighing $600N$ raises the centre of gravity of his body by $0.25m$ while taking each step of $1m$ length in jogging. If he jogs for $6km$, calculate the energy utilised by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting $10\%$ of energy intake in the form of food, calculate the energy equivalents of food that would be required to compensate energy utilised for jogging.

Answer 1

Step:1 Calculate the energy utilised by the adult.

Formula Used: $E=mgh$

In $6km$ there are $6000$ steps.

In one step energy utilised is $E=mgh$

$\therefore$ In $6000$ steps $E=6000\left(mg\right)h$

$=6000\times 600\times 0.25$

$=9\times {10}^{5}J$.

Step:2 Calculate the energy equivalents of food that would be required to compensate energy utilised for jogging.

As the above is $10\%$ of energy intake.

Therefore, the intake energy $=10E=9\times {10}^{6}J$.

Final Answer: $9\times {10}^{6}J$.