Question

An adult weighing $600N$ ralses the center of gravity of his body by $0.25m$ while taking each step of $1m$ length in jogging. If he jogs for $6km$, calculate the energy utilized by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting $10\%$ of energy intake in the from of food, calculate the energy equivalent of food that would be required to compensate energy utilized for jogging.

Answer 1

Energy used up by raising the centre of gravity by $0.25m$ by Jogger in one step $=mgh$
$mg=600N$
$h=0.25m$
$\therefore$ Number of steps in $6km=\frac{6000m}{1m}=6000$ steps
Energy utilised in $6000\times 600\times 0.25J$
Since $10\%$ of energy utilised in jogging
$\therefore$ Energy utilised in jogging $=\frac{10}{100}\times 6000\times 600\times 0.25$
$=360000\times 0.25$
$=90000J=9\times {10}^{4}J$