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Question

An adult weighing 600 N ralses the center of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs for 6 km, calculate the energy utilized by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting 10% of energy intake in the from of food, calculate the energy equivalent of food that would be required to compensate energy utilized for jogging.

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Solution

Energy used up by raising the centre of gravity by 0.25 m by Jogger in one step =mgh
mg=600 N
h=0.25m
Number of steps in 6 km=6000m1 m=6000 steps
Energy utilised in 6000×600×0.25 J
Since 10% of energy utilised in jogging
Energy utilised in jogging =10100×6000×600×0.25
=360000×0.25
=90000 J=9×104 J

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