An aeroplane accelerates from rest down a runaway at $3 {m s}^{- 2}$ for $18 s$ before it launches itself into the air. Determine the distance it covers before the take-off.
486

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Solution

The correct option is A 486
Given:
The acceleration of the aeroplane, $a = 3 {m s}^{- 2}$
Time spent by the plane on the runway, $t = 18 s$
Initial velocity, $u = 0$
Using the second equation of motion,
$s = ut + \frac{1}{2} {at}^{2}$
$⟹ s = \frac{1}{2} {at}^{2} = \frac{1}{2} \times 3 \times 18^{2} = 486 m$
The distance travelled by the aeroplane on the runway $= 486 m$

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