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Question

An aeroplane flying in the sky with a uniform speed of 200 m/s moves in a vertical circle of radius 400 m. The mass of the pilot is 70 kg. The force exerted by the pilot on the seat at the lowest point on the circle will be

A
4500 N
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B
6300 N
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C
7700 N
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D
770 N
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Solution

The correct option is C 7700 N
At the lowest point of the vertical circle :
Centripetal force Fc=Nmg(1)
wher N is the Normal force between pilot and the seat and this is the force we have to find
From Equation (1) we get:
mv2r=NmgN=mv2r+mg
here m=70kg and r=400m andv=200m/s
So using the values in equation (1) and solving we get:
N= 7700 N

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