An aeroplane having a distance of 50 m between the edges of its wings is flying horizontally with a speed of 360 km/hr. If the vertical components of earth's magnetic field is $2 \times 10^{- 4} w b / m^{2},$ then induced emf between the edges of its wings will be

1 V

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3 V

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0.02 V

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12 V

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Solution

The correct option is A $1 V$
$\begin{matrix} I n d u c e d E m f e = B_{v} v l v e l o c i t y o f p l a n e = \frac{3600 \times 1000}{3600} = 100 m / s ∴ e = 2 \times 10^{- 4} \times 100 \times 50 = 1 V H e n c e, t h e o p t i o n B i s t h e c o r r e c t a n s w e r . \end{matrix}$
Hence, the option $A$ is the correct answer.

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