An aeroplane moving horizontally with a speed of $180 k m / h r$ drops a food packet while flying at a height of $490 m$ . The horizontal range of the packet is:

180 m

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980 m

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500 m

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670 m

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Solution

The correct options are
A $180 m$
B $670 m$
C $500 m$

Time taken by packet to arrive on the ground t

$h = 0 \times t + \frac{1}{2} g t^{2} t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 490}{9.8}} = \sqrt{100} = 10 s e c .$

Distance traveled by the packet in horizontal direction during the same time D
$D = u \times t = 180 \times \frac{5}{18} \times 10 = 500 m$

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An aeroplane moving horizontally with a speed of 180km/hr drops a food packet while flying at a height of 490m. The horizontal range of the packet is:

The correct options are A 180m B 670m C 500m Time taken by packet to arrive on the ground t h=0×t+12gt2t=√2hg=√2×4909.8=√100=10 sec. Distance traveled by the packet in horizontal direction during the same time DD=u×t=180×518×10=500 m

An aeroplane moving horizontally with a speed of $180 k m / h r$ drops a food packet while flying at a height of $490 m$ . The horizontal range of the packet is: