Question

An aeroplane moving with 150 m/s drops a bomb from a height of 80 m so as to hit a target. What is the distance between the target and the point where the bomb is dropped? (given $g=10m/s^2$)

• A. 605.3 m
• B. 600 m
• C. 80 m
• D. 230 m

Answer 1

The correct option is A

605.3 m

The horizontal distance covered by bomb,
$BC=v_H\times \sqrt{\frac{2h}{g}}=150\sqrt{\frac{2\times 80}{10}}=600m$

$\therefore$ The distance of target from dropping point
$\therefore$ The distance of target from dropping point of bomb,
$AC$ = $\sqrt{A{B}^2+B{C}^2}$ = $\sqrt{(80{)}^2+(600{)}^2}$ = $605.3m$