An aeroplane revolves in a circle above the surface of the earth at a fixed height with speed $100$ km/hr. The change in velocity after completing $1 / 2$ revolution will be?

200

km/hr

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150

km/hr

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300

km/hr

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400

km/hr

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Solution

The correct option is A $200$ km/hr
Here underlying speed of the plane is 100km/h 100km/h in the upward heading (in the 2-D plane of this advanced screen).
After the plane finishes a large portion of a circle, it will point downwards. However, it will in any case have a similar speed of 100km/h100km/h. You can likewise call this −100km/h−100km/h in the upward course.
In this way, the adjustment in speed is equivalent to the underlying speed subtracted from the last speed.
Change in speed $- 100 k m / h - 100 k m / h - 100 k m / h - 100 k m / h$ n the upward heading.
Change in speed $- 200 k m / h - 200 k m / h$ n the upward heading.

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An aeroplane revolves in a circle above the surface of the earth at a fixed height with speed 100 km/hr. The change in velocity after completing 1/2 revolution will be?

An aeroplane revolves in a circle above the surface of the earth at a fixed height with speed $100$ km/hr. The change in velocity after completing $1 / 2$ revolution will be?