An aeroplane revolves in a circle above the surface of the earth at a fixed height with speed 100 km/hr. The magnitude of change in velocity after completing 1/2 revolution will be.

200 km/hr

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150 km/hr

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300 km/hr

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400 km/hr

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Solution

The correct option is A 200 km/hr
$\begin{matrix} Given, - \to V_{A} & = (100^i) k m / h r and, {\to V}_{B} & = (- 100^i) k m / h r \end{matrix}$

$\begin{matrix} Thus, change in velocity & = {\to V}_{B} - {\to V}_{A} = (- 200^i) k m / h r . \end{matrix}$

$Hence, magnitude of change in velocity = 200 k m / h r .$

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An aeroplane revolves in a circle above the surface of the earth at a fixed height with speed 100 km/hr. The magnitude of change in velocity after completing 1/2 revolution will be.

The correct option is A 200 km/hr Given, −→VA=(100^i)km/hr and, →VB=(−100^i)km/hr Thus, change in velocity =→VB−→VA=(−200^i)km/hr. Hence, magnitude of change in velocity =200 km/hr .