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Question

An aeroplane , taking off from a field, has a run of 500m. What is the acceleration if it leaves the ground in 10s from the start? Also find the take off velocity.

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Solution

Dear Student ,

Given: DISTANCE = s=500m Initial velocity =u=0 m/s Final velocity =V=? Time=t=10s From Second equation of motion: S=ut +12at2 500=0×10 +12×a×100 a=500/50=10m/s2 From V= u+ at =0+10×10 =100m/ s Therefore , acceleration is 10m/s2 and take off velocity is 100m/s.
Regards

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