An air bubble in a glass sphere having 4 cm diameter appears 1 cm from surface nearest to eye when looked along diameter. If $μ_{g, a} = 1.5$ , the distance of bubble from refracting surface is

1.2 cm

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3.2 cm

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2.8 cm

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1.6 cm

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Solution

The correct option is A 1.2 cm
By using
$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
where u = ?, v =-1 cm, $μ_{1} = 1.5, μ_{2} = 1, R = - 2 c m .$
$\frac{1}{- 1} - \frac{1.5}{u} = \frac{1 - 1.5}{(- 2)} \Rightarrow u = - \frac{6}{5} = - 1.2 c m .$

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An air bubble in a glass sphere having 4 cm diameter appears 1 cm from surface nearest to eye when looked along diameter. If μg,a=1.5, the distance of bubble from refracting surface is

The correct option is A 1.2 cmBy using μ2v−μ1u=μ2−μ1R where u = ?, v =-1 cm,μ1=1.5,μ2=1,R=−2cm. 1−1−1.5u=1−1.5(−2)⇒u=−65=−1.2cm.

An air bubble in a glass sphere having 4 cm diameter appears 1 cm from surface nearest to eye when looked along diameter. If $μ_{g, a} = 1.5$ , the distance of bubble from refracting surface is

The correct option is A 1.2 cm
By using
$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
where u = ?, v =-1 cm, $μ_{1} = 1.5, μ_{2} = 1, R = - 2 c m .$
$\frac{1}{- 1} - \frac{1.5}{u} = \frac{1 - 1.5}{(- 2)} \Rightarrow u = - \frac{6}{5} = - 1.2 c m .$