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Surface Tension

An air bubble...

Question

An air bubble of radius $0.1 c m$ is in a liquid having surface tension $0.06 N / m$ and density $10^{3} k g / m^{3}$ . The pressure inside the bubble is $1100 N m^{- 2}$ greater than the atmospheric pressure. At what depth is the bubble below the surface of the liquid? $(g = 9.8 m s^{- 2})$

0.20 m

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0.15 m

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0.1 m

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0.25 m

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Solution

The correct option is A $0.1 m$
$P_{i n s i d e} = P_{0} + ρ g h + \frac{2 T}{R}$
or
$P_{i n s i d e} - P_{0} = 10^{3} \times 9.8 \times h + \frac{2 \times 0.06}{0.1 \times 10^{- 2}} = 1100$
or
$h = 0.1 m$

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