Question

An air filled balloon is at a depth of 2 km below the water level in an ocean. Determine the normal stress on the balloon [atmospheric pressure $={10}^5$ Pa]

• A. $190\times {10}^{5}Pa$
• B. $196\times {10}^{5}Pa$
• C. $190\times {10}^{7}Pa$
• D. $196\times {10}^{7}Pa$

Answer 1

The correct option is B $196\times {10}^{5}Pa$

The stress an object can bear according to its area is called normal stress.

We have a balloon at a depth of 2 km below the water level in an ocean. We have to determine the normal stress balloon has if the atmospheric pressure is ${10}^5$.

To determine the normal stress we use the following formula:

Normal stress on the balloon : Normal stress $=$ Atmospheric pressure $+hdg$

By placing the given values,

$={10}^5+2000\times 1000\times 9.8$

$=196\times {10}^{5}Pa$