An air filled parallel plate condenser has a capacity of $2 p F$ . The separation of the plates is doubled and the inter-space between the plates is filled with wax. If the capacity is increased to $6$ pF, the dielectric constant of wax is.

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $6$
$C_{o l d} = \frac{ε_{o} A}{d} = 2 p F ⟶ (i)$
$C_{n e w} = \frac{K ε_{o} A}{2 d} = 6 p F ⟶ (i i)$
By Equating $(i)$ and $(i i)$
$\frac{K}{2} (2) p F = 6 p F$
$\Rightarrow K = 6$

Suggest Corrections

Similar questions

Q. An air-filled parallel plate capacitor has a capacity

2 p F

. The separation between the plates is doubled and the interspace is filled with wax, If the capacity is increased to 6 pF, the dielectric constant of the wax is :

Q. An air filled parallel plate capacitor has a capacitance

1 p F

. The separation between the plates is doubled and wax is inserted between the plates, then the capacitance becomes

2 p F

. What is the dielectric constant of wax ?

Q. The capacity of a parallel plate condenser without any dielectric is C. If the distance between the plates is doubled and the space between the plates is filled with a substance of dielectric constant

3

, the capacity of the condenser becomes:

The capacity of a parallel plate condenser with air medium is 60 $μ F$ having distance of separation d . If the space between the plates is filled with two slabs each of thickness d/2 and dielectric constants 4 and 8, the effective capacity becomes :

Q. If we increase '

d

' of a parallel condenser to '

2 d

' and fill wax to the whole empty space between its two plate, then capacitance increase from

1 p F

2 p F

. What is the dielectric constant of wax?

Join BYJU'S Learning Program

An air filled parallel plate condenser has a capacity of 2pF. The separation of the plates is doubled and the inter-space between the plates is filled with wax. If the capacity is increased to 6pF, the dielectric constant of wax is.

The correct option is D 6Cold=εoAd=2pF⟶(i)Cnew=KεoA2d=6pF⟶(ii)By Equating (i) and (ii)K2(2)pF=6pF⇒K=6

An air filled parallel plate condenser has a capacity of $2 p F$ . The separation of the plates is doubled and the inter-space between the plates is filled with wax. If the capacity is increased to $6$ pF, the dielectric constant of wax is.

The correct option is D $6$
$C_{o l d} = \frac{ε_{o} A}{d} = 2 p F ⟶ (i)$
$C_{n e w} = \frac{K ε_{o} A}{2 d} = 6 p F ⟶ (i i)$
By Equating $(i)$ and $(i i)$
$\frac{K}{2} (2) p F = 6 p F$
$\Rightarrow K = 6$