An aircraft executes a horizontal loop with a speed of $150 m/s$ with it's wings banked at an angle of $12^{\circ}$ . The radius of the loop is $(g = 10 {m/s}^{2}, tan 12^{\circ} = 0.21)$

10.7 km

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9.6 km

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7.4 km

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5.8 km

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Solution

The correct option is A $10.7 km$
Using the relation for the radius $(r)$ of loop
$tan θ = \frac{v^{2}}{r g}$
$or tan 12^{\circ} = \frac{(150)^{2}}{r \times 10}$
or $r = \frac{2250}{0.21} = 10.7 \times 10^{3} m = 10.7 km .$

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Similar questions

Q. An aircraft executes a horizontal loop with a speed of

150 m/s

with it's wings banked at an angle of

12^{\circ}

. The radius of the loop is

(g = 10 {m/s}^{2}, tan 12^{\circ} = 0.21)

An aircraft executes a horizontal loop with a speed of 150 m/s with its, wings banked at an angle of $120^{\circ}$ . The radius of the loop is $(g = 10 m / s^{2})$

Q. An aircraft executes a horizontal loop with a speed of

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m/s with its wings banked at an angle of

12^{o}

. The radius of the loop is

(g = 10 m / s^{2})

An aircraft executes a horizontal loop with a speed of 150 m/s with its, wings banked at an angle of $120^{\circ}$ . The radius of the loop is $(g = 10 m / s^{2})$

Q. An aircraft executes a horizontal loop at a speed of

720 k m h^{- 1}

with its wings banked at

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. What is the radius of the loop?
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g = 10 m s^{- 2}, t a n 15^{0} = 0.27

)

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An aircraft executes a horizontal loop with a speed of 150 m/s with it's wings banked at an angle of 12∘. The radius of the loop is (g=10 m/s2,tan12∘=0.21)

The correct option is A 10.7 kmUsing the relation for the radius (r) of loop tanθ=v2rg or tan12∘=(150)2r×10 or r=22500.21=10.7×103 m=10.7 km.

An aircraft executes a horizontal loop with a speed of $150 m/s$ with it's wings banked at an angle of $12^{\circ}$ . The radius of the loop is $(g = 10 {m/s}^{2}, tan 12^{\circ} = 0.21)$

The correct option is A $10.7 km$
Using the relation for the radius $(r)$ of loop
$tan θ = \frac{v^{2}}{r g}$
$or tan 12^{\circ} = \frac{(150)^{2}}{r \times 10}$
or $r = \frac{2250}{0.21} = 10.7 \times 10^{3} m = 10.7 km .$