An aircraft flying at a speed of 120 km/hr increases its speed by 6%. Find the speed of the aircraft after the increase.

127.2 \frac{k m}{h r}

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150.7 \frac{k m}{h r}

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7.2 \frac{k m}{h r}

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107.2 \frac{k m}{h r}

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Solution

The correct option is A $127.2 \frac{k m}{h r}$
The speed of an aircraft increases by $6 %$ from $120$ km/hr.
Hence, the increase in speed $= \frac{6}{100} \times 120$
$= 7.2$ km/hr

The speed of the aircraft after the increase $= 120 + 7.2$
$= 127.2$ km/hr

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An aircraft flying at a speed of 120 km/hr increases its speed by 6%. Find the speed of the aircraft after the increase.

The correct option is A 127.2kmhr The speed of an aircraft increases by 6% from 120 km/hr. Hence, the increase in speed =6100×120 =7.2 km/hr The speed of the aircraft after the increase =120+7.2 =127.2 km/hr

The correct option is A $127.2 \frac{k m}{h r}$
The speed of an aircraft increases by $6 %$ from $120$ km/hr.
Hence, the increase in speed $= \frac{6}{100} \times 120$
$= 7.2$ km/hr

The speed of the aircraft after the increase $= 120 + 7.2$
$= 127.2$ km/hr