Question

An airplane moving horizontally with a speed of 720 km/h drops a food pocket while flying at a height of 396.9 m. The time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/$se{c}^2$)

• A. 3 sec and 2000 m
• B. 5 sec and 500 m
• C. 8 sec and 1500 m
• D. 9 sec and 1800 m

Answer 1

The correct option is D

9 sec and 1800 m

t = $\sqrt{\frac{2h}{g}}$=$\sqrt{\frac{2\times 396.9}{9.8}}$ = 9sec and u = 720km/hr = 200m/s
$\therefore$R = u $\times$t = 200$\times$9 = 1800m