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Standard XII

Chemistry

General Mechanism of Electrophilic Aromatic Substitution

An alcohol X ...

Question

An alcohol X on heating with concentrated $H_{2} S O_{4}$ gives an alkene Y which can show geometrical isomerism.The alcohol X is?

C H_{3} C H_{2} O C H_{3}

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C H_{3} C H_{2} C H O

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C H_{3} C H_{2} C H_{2} O H

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C H_{3} C H_{2} C H (O H) C H_{3}

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Solution

The correct option is D $C H_{3} C H_{2} C H (O H) C H_{3}$
$C H_{3} C H_{2} C H (O H) C H_{3} H_{2} S O_{4} - --- \to C H_{3} - C H = C H - C H_{3}$
$X$ $Y$
Y show cis and trans isomerism. Hence, option D is correct.

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Similar questions

Q. An alcohol (A) on heating with concentrated

H_{2} S O_{4}

gives alkene (B), which shows geometrical isomerism. The compound (A) is:

Q. An alcohol X when treated with hot conc .

H_{2} S O_{4}

gave an alkene Y with formula

C_{4} H_{8}

. This alkene on ozonolysis gives a single product with molecular formula

C_{2} H_{4} O

. The alcohol is _______.

Q. An alcohol gave Lucas test in about 5 minutes. When the alcohol was treated with hot concentrated

H_{2} S O_{4}

, it gave an alkene of molecular formula

C_{4} H_{8}

which on ozonolysis gives single product with molecular formula

C_{2} H_{4} O

. The structure of alcohol is:

Q. An alkene

X

is obtained by dehydration of an alcohol

Y

X

on ozonolysis gives two molecules of ethanol for every molecule of the alkene.

X

and

Y

are:

tert-Butyl alcohol, when heated with $H_{2} S O_{4}$ , gives an alkene. Which of the following sequence will convert the alkene to 3-methylbutanoic acid?

1 - $H_{3} O^{+},$ hydrolysis

2 – treatment with $C N^{-}$

3 – $H B r,$ peroxide

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An alcohol X on heating with concentrated H2SO4 gives an alkene Y which can show geometrical isomerism.The alcohol X is?

The correct option is D CH3CH2CH(OH)CH3CH3CH2CH(OH)CH3H2SO4−−−−→CH3−CH=CH−CH3 X YY show cis and trans isomerism. Hence, option D is correct.

An alcohol X on heating with concentrated $H_{2} S O_{4}$ gives an alkene Y which can show geometrical isomerism.The alcohol X is?

The correct option is D $C H_{3} C H_{2} C H (O H) C H_{3}$
$C H_{3} C H_{2} C H (O H) C H_{3} H_{2} S O_{4} - --- \to C H_{3} - C H = C H - C H_{3}$
$X$ $Y$
Y show cis and trans isomerism. Hence, option D is correct.