An alcohol X when treated with hot conc . $H_{2} S O_{4}$ gave an alkene Y with formula $C_{4} H_{8}$ . This alkene on ozonolysis gives a single product with molecular formula $C_{2} H_{4} O$ . The alcohol is _______.

butan-1-ol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

butan-2-ol

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2-methylpropan-1-ol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2,2-dimethylbutan-1-ol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A butan-2-ol
Given that:
$X (R O H) + h o t c o n c H_{2} S O_{4} \to Y (C_{4} H_{8}, a l k e n e) o z o n o l y s i s - ----- \to C_{2} H_{4} O$
Ozonolysis reaction can be represented as:
$- C = C - o z o n o l y s i s - ----- \to - C = O + O = C -$
where all $C = C$ breaks to form $C = O$ . Since $C_{2} H_{4} O$ can be $C H_{3} C H = O$ . Also, it is the only product formed after ozonolysis i.e two moles of $C H_{3} C H = O$ are formed. thus the alkene from which it form will be $C H_{3} C H = C H C H_{3}$ i.e. $C_{4} H_{8}$ =Y
Dehydration reaction of an alcohol can be represented as:
$C H - C - O H H^{+} - - \to - C = C -$
Therefore the possible alcohol that can give $C H_{3} C H = C H C H_{3}$ will be $C H_{3} C H (O H) C H_{2} C H_{3}$ =X
Thus overall reaction is
$C H_{3} C H (O H) C H_{2} C H_{3} + h o t c o n c H_{2} S O_{4} \to C H_{3} C H = C H C H_{3} o z o n o l y s i s - ----- \to C H_{3} C H = O + O = C H C H_{3}$
The alcohol is 2-butanol.

Suggest Corrections

Similar questions

H_{2} {S O}_{4}

C_{2} H_{4} O

H_{2} S O_{4}

C_{4} H_{8}

C_{2} H_{4} O

C_{9} H_{18}

An alkene 'X' of the formula $C_{4} H_{8}$ on ozonolysis produced acetone and formaldehyde. The product obtained when 'X' reacts with HBr is

H_{2} S O_{4}

Join BYJU'S Learning Program