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Geometrical Isomerism

An alkene wit...

Question

An alkene with molecular formula $C_{6} H_{12}$ [A] on ozonolysis produces only one product [B] which given $2, 4 - D N P$ test positive but lodoform test negative. What will be the number of $α - H$ atoms present in that alkene [A]?

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Solution

The alkene is $C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3}$
as if gives only one product on ozonolysis.
$i . e . C H_{3} - C H_{2} - C H O$
It is an aldehyde and hence undergoes $2, 4 - D N P$ test positive. But it doesn't undergo idoform reaction.
The number of $\propto - H$ atom present in the alkene are $4.$
$C H_{3} - \propto | C H_{2} - C H = C H - \propto | C H_{2} - {C H}_{3}$

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